WebPRACTICE AND PROBLEM SOLVING, PAGES 219–221 12.m∠BEA=90°; rt. 13.m∠BCD=60 +60 =120°; obtuse 14.m∠ABC=30 +30 =60° m∠ABC=m∠ACB=m∠BAC; equiangular 15. PS ST PT −− ; equilateral 16. PS RS −− , so PS=RS=10; RP=17; isosc. 17. RT=10 +10 =20, RP=17, PT=10; scalene 18. Step 1Find z. 3z-1 =z+5 3z(190) =z+6 2z=6 z=3 Step 2Find side lengths. WebGiven that ABC has m∠B=133∘, a=12, and c=15, find the remaining side length b and angles A and C, rounded to the nearest tenth. In triangle Upper A Upper B Upper C, side Upper A …
In ABC, m∠A=32°, m∠B=25°, and a=18. Find c to the
WebJun 19, 2024 · 1 Answer Somebody N. Jun 19, 2024 ∠ABD = = 49∘ ∠CBD = 28∘ Explanation: ∠ABC = ∠ABD+ ∠CBD 77 = (3x +22) + (5x −17) 77 = 8x + 5 8x = 77− 5 = 72 x = 72 8 = 9 … WebEvaluate: 5m + 9n if m = -7 and n = 4 * a.71 b.1 c.-1 d.-71 Answer: Ans: b. 1 Step-by-step explanation: 5m + 9n where: m = -7 n = 4 Substitute the values 5m + 9n = 5 (-7) + 9 (4) = -35 + 36 = 1 Ans: b. 1 Answer:b.1 Step-by-step explanation:5m+9n m=-7 and n=4 =5 (-7)+9 (4) = (-35)+ (36) =1 2. 35. Nichis standing 80 m away from the base of the tower. mars vetrinary tests
The Triangles and its Properties Class 7 Extra Questions Maths …
WebBecause m∠ABE and m∠C both equal 52°, ∠ABE ≅ ∠C. By the Refl exive Property of Congruence (Theorem 2.2), ∠A ≅ ∠A. So, ABE ∼ ACD by the AA Similarity Theorem. b. You know ∠SVR ≅ ∠UVT by the Vertical Angles Congruence Theorem (Theorem 2.6). The diagram shows RS — UT —, so ∠S ≅ ∠U by the Alternate Interior WebThe measure of angle BAC can be calculated using the equation sin-1 (3.1/4.5) = x. What is the measure of angle BAC? Round to the nearest whole degree. 44 Which equation can be … WebMar 16, 2024 · ∠B = 2x + 25° Theorem used: Angles opposite to equal sides are equal. Sum of all angles of a triangle is 180° Calculation: According to angles opposite to equal sides are equal theorem. ⇒ AB = AC So, ∠B = ∠C = 2x + 25° According to sum of all angles of a triangle theorem ⇒ A + B + C = 180° ⇒ x + 15° + 2x + 25° + 2x + 25° = 180° ⇒ 5x + 65° = 180° mars victoria