In an ap sum of first 10 terms is-150
WebThe third term of an AP is four times the sixth term and the sum of the first ten terms is 150. Find a) The first term and the common difference b) The least number of terms of the Arithmetic Progression which must be taken for the sum to be negative Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution star_border WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty …
In an ap sum of first 10 terms is-150
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WebThe sum of the first two terms of an arithmetic progression is 18 and the sum of the first four terms is 52. Find the sum of the first eight terms. What is the sum of the series 2, 4, 6, 8, 10 ... WebLesson 4: Sum of first n terms of an AP. Arithmetic series intro. Arithmetic series formula. Worked example: arithmetic series (sum expression) Finding first term and common …
WebThe sum of n terms of an AP can be found using one of the following formulas: S n = n/2 (2a+ (n−1)d) S n = n/2 (a 1 +a n) Here, a = a 1 = the first term, d = the common difference, n = number of terms, a n = n th term, S n … WebConsider an arithmetic progression (AP) whose first term is a 1 (or) a and the common difference is d.. The sum of first n terms of an arithmetic progression when the n th term is NOT known is S n = (n/2) [2a + (n - 1) d]; The sum of first n terms of an arithmetic progression when the n th term(a n) is known is S n = n/2[a 1 + a n]; Example: Mr. Kevin …
WebJul 29, 2024 · In an AP, the sum of first ten terms is -150 and the sum of its next ten terms is -550. Find the A.P.I have provided the easiest solution of above question, ...... Webgiven S10 = a1+a2+...+10 = 150. But we know that: s10 = (a1+a10)*10/2 = 150. ==> a1+a10 = 150/5. ==> a1+a10 = 30. ==> a10 = 30 - a1...... (1) But a10 = a1 + 9*3 = a1 + 27. ==> a10 = …
WebIn an AP, the sum of first ten terms is -150 and the sum of next ten terms is -550. Find the AP.
WebThe sum of n terms of AP will be: Sum = a + (a+d) + (a+2d) …… + (l-2d) + (l-d) + l——————– (3) where l= a+ (n-1)d Writing in reverse order, the sum will still remain same. Sum =l+ (l-d)+ (l-2d)..…+ (a+2d)+ (a+d)+a——————- (4) Adding equations 3 and 4, we get 2 × Sum = (a+l)+ [ (a+d)+ (l-d)]………+ [ (l-d)+ (a+d)]+ (l+a)] crystal hip hop jewelryWebApr 11, 2024 · Given the sum of the first 10 terms of an AP is -150 and the sum of the next ten terms which means Sum of first 20 terms-Sum of first 10 terms is -530. Let the first … dwhd770wpr panel specsWebIn an A.P. the sum of first ten terms is -150 and the sum of its next 10 term is -550. Find the A.P. Answer: Solution: The sum of n terms of AP is the addition of first n terms of the … crystal hipolitocrystal hilton in washington dcWebMar 19, 2024 · Given that sum of the first 10 terms of an A.P. is -150. S10 = -150 And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum of next 10 terms S20 = -150 + -550 = -700 Now, having S10 = 10 2 10 2 (2a + (10 − 1)d) -150 = 5 (2a + 9d) -30 = 2a + 9d 2a + 9d = -30 . . . . (1) And, crystal hippie headbandWebOct 20, 2024 · In an AP the sum of first ten terms is -150 and the sum of its next 10 terms is -550. Find the AP. Is this the question you’re looking for? Advertisement Expert-Verified Answer 49 people found it helpful Hey there !! Let a be the first term and d be the common difference of the given AP . S₁₀ = -150. ⇒ Sn = n/2 [ 2a + (n-1)d] dwhd770wpr partsWebMar 19, 2024 · Given that sum of the first 10 terms of an A.P. is -150. S10 = -150. And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum … crystal hippie aesthetic