WebHere is the documentation from scala: def -- [B >: A] (that: List [B]) : List [B] Computes the difference between this list and the given list that. that the list of elements to remove from this list. returns this list without the elements of the given list that. deprecated: use list1 filterNot (list2 contains) instead WebScala tuple combines a fixed number of items together so that they can be passed around as a whole. Unlike an array or list, a tuple can hold objects with different types but they are also immutable. The following is an example of a tuple holding an integer, a string, and the console. val t = (1, "hello", Console) Which is syntactic sugar ...
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WebMar 31, 2024 · Without using loops: * symbol is use to print the list elements in a single line with space. To print all elements in new lines or separated by comma use sep=”\n” or sep=”, ” respectively. WebApr 16, 2015 · scala> val l = List ("a", "b", "c") scala> l.lift (1) Some ("b") scala> l.lift (5) None Whenever you're performing an operation that may fail in this way it's great to use an Option and get the type system to help make sure you are handling the case where the element doesn't exist. Explanation:
WebJul 14, 2014 · Try this: val dup = List(1,1,1,2,3,4,5,5,6,100,101,101,102) dup.groupBy(identity).collect { case (x, List(_,_,_*)) => x } The groupBy associates each distinct integer with a list of its occurrences. The collect is basically map where non-matching elements are ignored. The match pattern following case will match integers x … WebJul 15, 2013 · If you use list instead, toString () method prints the actual elenents (not the hashCode) var a = List (1,2,3) println (a) or var a = Array (1,2,3) println (a.toList) Share Improve this answer Follow answered Jul 13, 2013 …
WebFind many great new & used options and get the best deals for MILAN ITALY PHOTOGRAPH PIAZZA DELLA SCALA, GALLERIA LARGE ALBUMEN PRINT 1870s at the best online prices at eBay! Free shipping for many products! WebJan 25, 2011 · scala> val data =List ( ("2001",13.1), ("2009",3.1), ("2004",24.0), ("2011",1.11)) data: List [ (java.lang.String, Double)] = List ( (2001,13.1), (2009,3.1), (2004,24.0), (2011,1.11)) scala> data.foreach (x => println (x._1+" "+x._2)) 2001 13.1 2009 3.1 2004 24.0 2011 1.11 Share Improve this answer Follow answered Jan 25, 2011 at 12:17
WebFeb 10, 2016 · 1 - Declare your List val myCharList: List [Char] = List (' (',')',' (',')') 2 - Define your method def printList ( chars: List [Char] ): Boolean = { if ( chars.isEmpty ) true //every item of the list has been printed else { println ( chars.head ) printList ( chars.tail ) } } 3 - Call the …
WebJul 18, 2024 · 20 In scala foreach loop if I have list val a = List ("a","b","c","d") I can print them without a pattern matching like this a.foreach (c => println (c)) But, if I have a tuple like this val v = Vector ( (1,9), (2,8), (3,7), (4,6), (5,5)) why should I have to use v.foreach { case (i,j) => println (i, j) } a pattern matching case { brackets impact of stress on schizophreniaWebSyntax of Scala List In Scala, we can create a list in two ways We can assign value to the list while creating the list object without defining the data type. We can also create a list with data type declaration with it so only that type of data we can assign to a specific list later. impact of stress on sleepWebIdiom #7 Iterate over list indexes and values. Print each index i with its value x from an array-like collection items impact of stress on youth conclusionWebApr 17, 2024 · In Scala, list is defined under scala.collection.immutable package. A list is a collection of same type elements which contains immutable data. we generally use last function to print last element of a list. Below are the examples to find the last element of a given list in Scala. Simply print last element of a list. impact of stress on productivityimpact of stress on diabetesWebUsing the Set force the list to have unique values: def maxes2 [A] (n:Int) (l:Traversable [A]) (implicit o:Ordering [A]) = l.foldLeft (List.empty [A]) { (xs,y) => import o._ if (xs.size < n) (y::xs).sort (lt _) else { val first = xs.head if (first < y) (y:: (xs - first)).sort (lt _) else xs } } Share Improve this answer impact of stress on performanceWebNov 15, 2012 · scala.List is immutable, meaning you cannot update it in place. If you want to create a copy of your List which contains the updated mapping, you can do the following: val updated = l2.updated ( 2, 55 ) There are mutable ordered sequence types as well, in scala.collection.mutable, such as Buffer types which seem more like what you want. list the four stages of the cell cycle